This Problem and Solution Deformations and Axial Loading (Mechanic of Materials)

2.2  A 4,8-ft-long steel wire od 1/4 –in diameter steel wire is subjected to a 750-lb tensile load. Knowing that E = 29 x 10⁶ psi, determine (a) the elongation of the wire, (b) the corresponding normal stress.

Guru Solution (a)

L    = 4,8 ft

= 57,6 in

A   = p/4 . d²

= p/4 . (1/4)²

= 49,087 x 10^-3 in²

d        = (P.L)/(A.E)

= (750 x 57,6)/ (49,087 x10^-3)(29 x 10⁶)

= 30,3 x 10-3 in

= 0,0303 in

Guru Solution (b)

d    = P/A

            = 750/ 49.087 x 10-3

            = 15,28 x 103 psi

            = 15,28 ksi

PROBLEM AND SOLUTION

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